Solve 16n^4-2n*2n*2n*2n

$$16 n ^ { 4 } - 2 n \cdot 2 n \cdot 2 n \cdot 2 n$$

Evaluate

$$0$$

Solution Steps

Multiply n and n to get n^{2}.

$$16n^{4}-2n^{2}\times 2\times 2n\times 2n$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$16n^{4}-2n^{3}\times 2\times 2\times 2n$$

To multiply powers of the same base, add their exponents. Add 3 and 1 to get 4.

$$16n^{4}-2n^{4}\times 2\times 2\times 2$$

Multiply 2 and 2 to get 4.

$$16n^{4}-4n^{4}\times 2\times 2$$

Multiply 4 and 2 to get 8.

$$16n^{4}-8n^{4}\times 2$$

Multiply 8 and 2 to get 16.

$$16n^{4}-16n^{4}$$

Combine 16n^{4} and -16n^{4} to get 0.

$$0$$

Factor

$$0$$

Solution Steps

Factor out 16.

$$16\left(n^{4}-nnnn\right)$$

Consider n^{4}-n^{4}. Factor out n^{4}.

$$0$$