Solve 16n^2-128x+1x=0

$$16 n ^ { 2 } - 128 x + 1 x = 0$$

Solve for x

$$x=\frac{16n^{2}}{127}$$

Steps for Solving Linear Equation

Combine -128x and 1x to get -127x.

$$16n^{2}-127x=0$$

Subtract 16n^{2} from both sides. Anything subtracted from zero gives its negation.

$$-127x=-16n^{2}$$

Divide both sides by -127.

$$\frac{-127x}{-127}=-\frac{16n^{2}}{-127}$$

Dividing by -127 undoes the multiplication by -127.

$$x=-\frac{16n^{2}}{-127}$$

Divide -16n^{2} by -127.

$$x=\frac{16n^{2}}{127}$$

Solve for n (complex solution)

$$n=-\frac{\sqrt{127x}}{4}$$

$$n=\frac{\sqrt{127x}}{4}$$

Solve for n

$$n=\frac{\sqrt{127x}}{4}$$

$$n=-\frac{\sqrt{127x}}{4}\text{, }x\geq 0$$