Solve 16m^2-64n^2

$$16 m ^ { 2 } - 64 n ^ { 2 }$$

Factor

$$16\left(m-2n\right)\left(m+2n\right)$$

Solution Steps

Factor out 16.

$$16\left(m^{2}-4n^{2}\right)$$

Consider m^{2}-4n^{2}. Rewrite m^{2}-4n^{2} as m^{2}-\left(2n\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(m-2n\right)\left(m+2n\right)$$

Rewrite the complete factored expression.

$$16\left(m-2n\right)\left(m+2n\right)$$

Evaluate

$$16\left(m^{2}-4n^{2}\right)$$