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\left(4a^{3}-9b^{4}\right)\left(4a^{3}+9b^{4}\right)
Rewrite 16a^{6}-81b^{8} as \left(4a^{3}\right)^{2}-\left(9b^{4}\right)^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).