Solve 16a^2-280a+12x=0

$$16 a ^ { 2 } - 280 a + 12 x = 0$$

Solve for x

$$x=-\frac{2a\left(2a-35\right)}{3}$$

Steps for Solving Linear Equation

Subtract 16a^{2} from both sides. Anything subtracted from zero gives its negation.

$$-280a+12x=-16a^{2}$$

Add 280a to both sides.

$$12x=-16a^{2}+280a$$

The equation is in standard form.

$$12x=280a-16a^{2}$$

Divide both sides by 12.

$$\frac{12x}{12}=\frac{8a\left(35-2a\right)}{12}$$

Dividing by 12 undoes the multiplication by 12.

$$x=\frac{8a\left(35-2a\right)}{12}$$

Divide 8a\left(35-2a\right) by 12.

$$x=\frac{2a\left(35-2a\right)}{3}$$

Solve for a (complex solution)

$$a=\frac{\sqrt{1225-12x}+35}{4}$$

$$a=\frac{-\sqrt{1225-12x}+35}{4}$$

Solve for a

$$a=\frac{\sqrt{1225-12x}+35}{4}$$

$$a=\frac{-\sqrt{1225-12x}+35}{4}\text{, }x\leq \frac{1225}{12}$$