Solve for a
a\leq -\frac{250}{3}
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16a+1000-10a\leq 500
Use the distributive property to multiply 10 by 100-a.
6a+1000\leq 500
Combine 16a and -10a to get 6a.
6a\leq 500-1000
Subtract 1000 from both sides.
6a\leq -500
Subtract 1000 from 500 to get -500.
a\leq \frac{-500}{6}
Divide both sides by 6. Since 6 is positive, the inequality direction remains the same.
a\leq -\frac{250}{3}
Reduce the fraction \frac{-500}{6} to lowest terms by extracting and canceling out 2.
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