Solve for A
A=\frac{4B+C}{16}
Solve for B
B=-\frac{C}{4}+4A
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16A=1C+4B
Add 4B to both sides.
16A=4B+C
Reorder the terms.
\frac{16A}{16}=\frac{4B+C}{16}
Divide both sides by 16.
A=\frac{4B+C}{16}
Dividing by 16 undoes the multiplication by 16.
A=\frac{B}{4}+\frac{C}{16}
Divide 4B+C by 16.
-4B=1C-16A
Subtract 16A from both sides.
-4B=-16A+C
Reorder the terms.
-4B=C-16A
The equation is in standard form.
\frac{-4B}{-4}=\frac{C-16A}{-4}
Divide both sides by -4.
B=\frac{C-16A}{-4}
Dividing by -4 undoes the multiplication by -4.
B=-\frac{C}{4}+4A
Divide -16A+C by -4.
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