Skip to main content
Factor
Tick mark Image
Evaluate
Tick mark Image

Similar Problems from Web Search

Share

16a^{2}+6a-3=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
a=\frac{-6±\sqrt{6^{2}-4\times 16\left(-3\right)}}{2\times 16}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
a=\frac{-6±\sqrt{36-4\times 16\left(-3\right)}}{2\times 16}
Square 6.
a=\frac{-6±\sqrt{36-64\left(-3\right)}}{2\times 16}
Multiply -4 times 16.
a=\frac{-6±\sqrt{36+192}}{2\times 16}
Multiply -64 times -3.
a=\frac{-6±\sqrt{228}}{2\times 16}
Add 36 to 192.
a=\frac{-6±2\sqrt{57}}{2\times 16}
Take the square root of 228.
a=\frac{-6±2\sqrt{57}}{32}
Multiply 2 times 16.
a=\frac{2\sqrt{57}-6}{32}
Now solve the equation a=\frac{-6±2\sqrt{57}}{32} when ± is plus. Add -6 to 2\sqrt{57}.
a=\frac{\sqrt{57}-3}{16}
Divide -6+2\sqrt{57} by 32.
a=\frac{-2\sqrt{57}-6}{32}
Now solve the equation a=\frac{-6±2\sqrt{57}}{32} when ± is minus. Subtract 2\sqrt{57} from -6.
a=\frac{-\sqrt{57}-3}{16}
Divide -6-2\sqrt{57} by 32.
16a^{2}+6a-3=16\left(a-\frac{\sqrt{57}-3}{16}\right)\left(a-\frac{-\sqrt{57}-3}{16}\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \frac{-3+\sqrt{57}}{16} for x_{1} and \frac{-3-\sqrt{57}}{16} for x_{2}.