Solve 16*(3/4)^2+2*(1/3)^2-3

$$16 \times ( \frac { 3 } { 4 } ) ^ { 2 } + 2 \times ( \frac { 1 } { 3 } ) ^ { 2 } - 3$$

Evaluate

$$\frac{56}{9}\approx 6.222222222$$

Solution Steps

Calculate \frac{3}{4} to the power of 2 and get \frac{9}{16}.

$$16\times \frac{9}{16}+2\times \left(\frac{1}{3}\right)^{2}-3$$

Cancel out 16 and 16.

$$9+2\times \left(\frac{1}{3}\right)^{2}-3$$

Calculate \frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$9+2\times \frac{1}{9}-3$$

Multiply 2 and \frac{1}{9} to get \frac{2}{9}.

$$9+\frac{2}{9}-3$$

Convert 9 to fraction \frac{81}{9}.

$$\frac{81}{9}+\frac{2}{9}-3$$

Since \frac{81}{9} and \frac{2}{9} have the same denominator, add them by adding their numerators.

$$\frac{81+2}{9}-3$$

Add 81 and 2 to get 83.

$$\frac{83}{9}-3$$

Convert 3 to fraction \frac{27}{9}.

$$\frac{83}{9}-\frac{27}{9}$$

Since \frac{83}{9} and \frac{27}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{83-27}{9}$$

Subtract 27 from 83 to get 56.

$$\frac{56}{9}$$

Factor

$$\frac{2 ^ {3} \cdot 7}{3 ^ {2}} = 6\frac{2}{9} = 6.222222222222222$$