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\frac{48+1}{3}\left(3-\frac{1\times 7+2}{7}\right)
Multiply 16 and 3 to get 48.
\frac{49}{3}\left(3-\frac{1\times 7+2}{7}\right)
Add 48 and 1 to get 49.
\frac{49}{3}\left(3-\frac{7+2}{7}\right)
Multiply 1 and 7 to get 7.
\frac{49}{3}\left(3-\frac{9}{7}\right)
Add 7 and 2 to get 9.
\frac{49}{3}\left(\frac{21}{7}-\frac{9}{7}\right)
Convert 3 to fraction \frac{21}{7}.
\frac{49}{3}\times \frac{21-9}{7}
Since \frac{21}{7} and \frac{9}{7} have the same denominator, subtract them by subtracting their numerators.
\frac{49}{3}\times \frac{12}{7}
Subtract 9 from 21 to get 12.
\frac{49\times 12}{3\times 7}
Multiply \frac{49}{3} times \frac{12}{7} by multiplying numerator times numerator and denominator times denominator.
\frac{588}{21}
Do the multiplications in the fraction \frac{49\times 12}{3\times 7}.
28
Divide 588 by 21 to get 28.