Solve 16div(-2)^3-(-1/8)*(-4)

$$16 \div ( - 2 ) ^ { 3 } - ( - \frac { 1 } { 8 } ) \times ( - 4 )$$

Evaluate

$$-\frac{5}{2}=-2.5$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$\frac{16}{-8}-\left(-\frac{1}{8}\left(-4\right)\right)$$

Divide 16 by -8 to get -2.

$$-2-\left(-\frac{1}{8}\left(-4\right)\right)$$

Express -\frac{1}{8}\left(-4\right) as a single fraction.

$$-2-\frac{-\left(-4\right)}{8}$$

Multiply -1 and -4 to get 4.

$$-2-\frac{4}{8}$$

Reduce the fraction \frac{4}{8} to lowest terms by extracting and canceling out 4.

$$-2-\frac{1}{2}$$

Convert -2 to fraction -\frac{4}{2}.

$$-\frac{4}{2}-\frac{1}{2}$$

Since -\frac{4}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-4-1}{2}$$

Subtract 1 from -4 to get -5.

$$-\frac{5}{2}$$

Factor

$$-\frac{5}{2} = -2\frac{1}{2} = -2.5$$