Solve 16div2+40div7-3

$$16 \div 2+40 \div 7-3$$

Evaluate

$$\frac{75}{7}\approx 10.714285714$$

Solution Steps

Divide 16 by 2 to get 8.

$$8+\frac{40}{7}-3$$

Convert 8 to fraction \frac{56}{7}.

$$\frac{56}{7}+\frac{40}{7}-3$$

Since \frac{56}{7} and \frac{40}{7} have the same denominator, add them by adding their numerators.

$$\frac{56+40}{7}-3$$

Add 56 and 40 to get 96.

$$\frac{96}{7}-3$$

Convert 3 to fraction \frac{21}{7}.

$$\frac{96}{7}-\frac{21}{7}$$

Since \frac{96}{7} and \frac{21}{7} have the same denominator, subtract them by subtracting their numerators.

$$\frac{96-21}{7}$$

Subtract 21 from 96 to get 75.

$$\frac{75}{7}$$

Factor

$$\frac{3 \cdot 5 ^ {2}}{7} = 10\frac{5}{7} = 10.714285714285714$$