Solve 16div-2^3--1/8-4

$$16 \div { -2 }^{ 3 } -- \frac{ 1 }{ 8 } -4$$

Evaluate

$$-\frac{47}{8}=-5.875$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$\frac{16}{-8}-\left(-\frac{1}{8}\right)-4$$

Divide 16 by -8 to get -2.

$$-2-\left(-\frac{1}{8}\right)-4$$

The opposite of -\frac{1}{8} is \frac{1}{8}.

$$-2+\frac{1}{8}-4$$

Convert -2 to fraction -\frac{16}{8}.

$$-\frac{16}{8}+\frac{1}{8}-4$$

Since -\frac{16}{8} and \frac{1}{8} have the same denominator, add them by adding their numerators.

$$\frac{-16+1}{8}-4$$

Add -16 and 1 to get -15.

$$-\frac{15}{8}-4$$

Convert 4 to fraction \frac{32}{8}.

$$-\frac{15}{8}-\frac{32}{8}$$

Since -\frac{15}{8} and \frac{32}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-15-32}{8}$$

Subtract 32 from -15 to get -47.

$$-\frac{47}{8}$$

Factor

$$-\frac{47}{8} = -5\frac{7}{8} = -5.875$$