Solve 16^2-6^-3-3^2*3^-3=

$$16 ^ { 2 } - 6 ^ { - 3 } - 3 ^ { 2 } \cdot 3 ^ { - 3 } =$$

Evaluate

$$\frac{55223}{216}\approx 255.662037037$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 2 and -3 to get -1.

$$16^{2}-6^{-3}-3^{-1}$$

Calculate 16 to the power of 2 and get 256.

$$256-6^{-3}-3^{-1}$$

Calculate 6 to the power of -3 and get \frac{1}{216}.

$$256-\frac{1}{216}-3^{-1}$$

Subtract \frac{1}{216} from 256 to get \frac{55295}{216}.

$$\frac{55295}{216}-3^{-1}$$

Calculate 3 to the power of -1 and get \frac{1}{3}.

$$\frac{55295}{216}-\frac{1}{3}$$

Subtract \frac{1}{3} from \frac{55295}{216} to get \frac{55223}{216}.

$$\frac{55223}{216}$$

Factor

$$\frac{7 ^ {4} \cdot 23}{2 ^ {3} \cdot 3 ^ {3}} = 255\frac{143}{216} = 255.66203703703704$$