Solve for x
x=\sqrt{5}\approx 2.236067977
x=-\sqrt{5}\approx -2.236067977
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16x^{2}=80
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x^{2}.
x^{2}=\frac{80}{16}
Divide both sides by 16.
x^{2}=5
Divide 80 by 16 to get 5.
x=\sqrt{5} x=-\sqrt{5}
Take the square root of both sides of the equation.
16x^{2}=80
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x^{2}.
16x^{2}-80=0
Subtract 80 from both sides.
x=\frac{0±\sqrt{0^{2}-4\times 16\left(-80\right)}}{2\times 16}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 16 for a, 0 for b, and -80 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 16\left(-80\right)}}{2\times 16}
Square 0.
x=\frac{0±\sqrt{-64\left(-80\right)}}{2\times 16}
Multiply -4 times 16.
x=\frac{0±\sqrt{5120}}{2\times 16}
Multiply -64 times -80.
x=\frac{0±32\sqrt{5}}{2\times 16}
Take the square root of 5120.
x=\frac{0±32\sqrt{5}}{32}
Multiply 2 times 16.
x=\sqrt{5}
Now solve the equation x=\frac{0±32\sqrt{5}}{32} when ± is plus.
x=-\sqrt{5}
Now solve the equation x=\frac{0±32\sqrt{5}}{32} when ± is minus.
x=\sqrt{5} x=-\sqrt{5}
The equation is now solved.
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Limits
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