Solve 16+5*[-32-(-7)]-sqrt[3]{(-4)^3-[(-2)^2]}

$$16 + 5 \cdot [ - 32 - ( - 7 ) ] - \sqrt[ 3 ] { ( - 4 ) ^ { 3 } - [ ( - 2 ) ^ { 2 } ] }$$

Evaluate

$$\sqrt[3]{68}-109\approx -104.918344898$$

Solution Steps

The opposite of -7 is 7.

$$16+5\left(-32+7\right)-\sqrt[3]{\left(-4\right)^{3}-\left(-2\right)^{2}}$$

Add -32 and 7 to get -25.

$$16+5\left(-25\right)-\sqrt[3]{\left(-4\right)^{3}-\left(-2\right)^{2}}$$

Multiply 5 and -25 to get -125.

$$16-125-\sqrt[3]{\left(-4\right)^{3}-\left(-2\right)^{2}}$$

Subtract 125 from 16 to get -109.

$$-109-\sqrt[3]{\left(-4\right)^{3}-\left(-2\right)^{2}}$$

Calculate -4 to the power of 3 and get -64.

$$-109-\sqrt[3]{-64-\left(-2\right)^{2}}$$

Calculate -2 to the power of 2 and get 4.

$$-109-\sqrt[3]{-64-4}$$

Subtract 4 from -64 to get -68.

$$-109-\sqrt[3]{-68}$$