Solve 1500+(40/2*40-24/-24-33)

$$1500+( \frac{ 40 }{ 2 \times 40 } - \frac{ 24 }{ -24-33 } )$$

Evaluate

$$\frac{57035}{38}\approx 1500.921052632$$

Solution Steps

Multiply 2 and 40 to get 80.

$$1500+\frac{40}{80}-\frac{24}{-24-33}$$

Reduce the fraction \frac{40}{80} to lowest terms by extracting and canceling out 40.

$$1500+\frac{1}{2}-\frac{24}{-24-33}$$

Convert 1500 to fraction \frac{3000}{2}.

$$\frac{3000}{2}+\frac{1}{2}-\frac{24}{-24-33}$$

Since \frac{3000}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.

$$\frac{3000+1}{2}-\frac{24}{-24-33}$$

Add 3000 and 1 to get 3001.

$$\frac{3001}{2}-\frac{24}{-24-33}$$

Subtract 33 from -24 to get -57.

$$\frac{3001}{2}-\frac{24}{-57}$$

Reduce the fraction \frac{24}{-57} to lowest terms by extracting and canceling out 3.

$$\frac{3001}{2}-\left(-\frac{8}{19}\right)$$

The opposite of -\frac{8}{19} is \frac{8}{19}.

$$\frac{3001}{2}+\frac{8}{19}$$

Least common multiple of 2 and 19 is 38. Convert \frac{3001}{2} and \frac{8}{19} to fractions with denominator 38.

$$\frac{57019}{38}+\frac{16}{38}$$

Since \frac{57019}{38} and \frac{16}{38} have the same denominator, add them by adding their numerators.

$$\frac{57019+16}{38}$$

Add 57019 and 16 to get 57035.

$$\frac{57035}{38}$$

Factor

$$\frac{5 \cdot 11 \cdot 17 \cdot 61}{2 \cdot 19} = 1500\frac{35}{38} = 1500.921052631579$$