Solve 150x+(3000-60x)/40*120leq7800

$$150 x + \frac { ( 3000 - 60 x ) } { 40 } \times 120 \leq 7800$$

Solve for x

$$x\geq 40$$

Solution Steps

Multiply both sides of the equation by 40. Since 40 is positive, the inequality direction remains the same.

$$6000x+\left(3000-60x\right)\times 120\leq 312000$$

Use the distributive property to multiply 3000-60x by 120.

$$6000x+360000-7200x\leq 312000$$

Combine 6000x and -7200x to get -1200x.

$$-1200x+360000\leq 312000$$

Subtract 360000 from both sides.

$$-1200x\leq 312000-360000$$

Subtract 360000 from 312000 to get -48000.

$$-1200x\leq -48000$$

Divide both sides by -1200. Since -1200 is negative, the inequality direction is changed.

$$x\geq \frac{-48000}{-1200}$$

Divide -48000 by -1200 to get 40.

$$x\geq 40$$