Solve 15-4+3-12-5*2+5+16/4-5+10-2^3

$$15-4+3-12-5 \cdot 2+5+ \frac{ 16 }{ 4 } -5+10- { 2 }^{ 3 }$$

Evaluate

$$-2$$

Solution Steps

Subtract 4 from 15 to get 11.

$$11+3-12-5\times 2+5+\frac{16}{4}-5+10-2^{3}$$

Add 11 and 3 to get 14.

$$14-12-5\times 2+5+\frac{16}{4}-5+10-2^{3}$$

Subtract 12 from 14 to get 2.

$$2-5\times 2+5+\frac{16}{4}-5+10-2^{3}$$

Multiply 5 and 2 to get 10.

$$2-10+5+\frac{16}{4}-5+10-2^{3}$$

Subtract 10 from 2 to get -8.

$$-8+5+\frac{16}{4}-5+10-2^{3}$$

Add -8 and 5 to get -3.

$$-3+\frac{16}{4}-5+10-2^{3}$$

Divide 16 by 4 to get 4.

$$-3+4-5+10-2^{3}$$

Add -3 and 4 to get 1.

$$1-5+10-2^{3}$$

Subtract 5 from 1 to get -4.

$$-4+10-2^{3}$$

Add -4 and 10 to get 6.

$$6-2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$6-8$$

Subtract 8 from 6 to get -2.

$$-2$$

Factor

$$-2$$