Solve 15=5+(1-2100/2400)x

$$15=5+(1- \frac{ 2100 }{ 2400 } )x$$

Solve for x

$$x=80$$

Steps for Solving Linear Equation

Reduce the fraction \frac{2100}{2400} to lowest terms by extracting and canceling out 300.

$$15=5+\left(1-\frac{7}{8}\right)x$$

Convert 1 to fraction \frac{8}{8}.

$$15=5+\left(\frac{8}{8}-\frac{7}{8}\right)x$$

Since \frac{8}{8} and \frac{7}{8} have the same denominator, subtract them by subtracting their numerators.

$$15=5+\frac{8-7}{8}x$$

Subtract 7 from 8 to get 1.

$$15=5+\frac{1}{8}x$$

Swap sides so that all variable terms are on the left hand side.

$$5+\frac{1}{8}x=15$$

Subtract 5 from both sides.

$$\frac{1}{8}x=15-5$$

Subtract 5 from 15 to get 10.

$$\frac{1}{8}x=10$$

Multiply both sides by 8, the reciprocal of \frac{1}{8}.

$$x=10\times 8$$

Multiply 10 and 8 to get 80.

$$x=80$$