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3\left(5x^{3}-29x^{2}-6x\right)
Factor out 3.
x\left(5x^{2}-29x-6\right)
Consider 5x^{3}-29x^{2}-6x. Factor out x.
a+b=-29 ab=5\left(-6\right)=-30
Consider 5x^{2}-29x-6. Factor the expression by grouping. First, the expression needs to be rewritten as 5x^{2}+ax+bx-6. To find a and b, set up a system to be solved.
1,-30 2,-15 3,-10 5,-6
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -30.
1-30=-29 2-15=-13 3-10=-7 5-6=-1
Calculate the sum for each pair.
a=-30 b=1
The solution is the pair that gives sum -29.
\left(5x^{2}-30x\right)+\left(x-6\right)
Rewrite 5x^{2}-29x-6 as \left(5x^{2}-30x\right)+\left(x-6\right).
5x\left(x-6\right)+x-6
Factor out 5x in 5x^{2}-30x.
\left(x-6\right)\left(5x+1\right)
Factor out common term x-6 by using distributive property.
3x\left(x-6\right)\left(5x+1\right)
Rewrite the complete factored expression.