Solve 15a1+5baz=15

$$15 a 1 + 5 b a z = 15$$

Solve for a (complex solution)

$$\left\{\begin{matrix}a=-\frac{3\left(a_{1}-1\right)}{bz}\text{, }&z\neq 0\text{ and }b\neq 0\\a\in \mathrm{C}\text{, }&\left(b=0\text{ or }z=0\right)\text{ and }a_{1}=1\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 15a_{1} from both sides.

$$5baz=15-15a_{1}$$

The equation is in standard form.

$$5bza=15-15a_{1}$$

Divide both sides by 5bz.

$$\frac{5bza}{5bz}=\frac{15-15a_{1}}{5bz}$$

Dividing by 5bz undoes the multiplication by 5bz.

$$a=\frac{15-15a_{1}}{5bz}$$

Divide 15-15a_{1} by 5bz.

$$a=\frac{3\left(1-a_{1}\right)}{bz}$$

Solve for a

$$\left\{\begin{matrix}a=-\frac{3\left(a_{1}-1\right)}{bz}\text{, }&z\neq 0\text{ and }b\neq 0\\a\in \mathrm{R}\text{, }&\left(b=0\text{ or }z=0\right)\text{ and }a_{1}=1\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 15a_{1} from both sides.

$$5baz=15-15a_{1}$$

The equation is in standard form.

$$5bza=15-15a_{1}$$

Divide both sides by 5bz.

$$\frac{5bza}{5bz}=\frac{15-15a_{1}}{5bz}$$

Dividing by 5bz undoes the multiplication by 5bz.

$$a=\frac{15-15a_{1}}{5bz}$$

Divide 15-15a_{1} by 5bz.

$$a=\frac{3\left(1-a_{1}\right)}{bz}$$

Solve for a_1

$$a_{1}=-\frac{abz}{3}+1$$

Steps for Solving Linear Equation

Subtract 5baz from both sides.

$$15a_{1}=15-5baz$$

The equation is in standard form.

$$15a_{1}=15-5abz$$

Divide both sides by 15.

$$\frac{15a_{1}}{15}=\frac{15-5abz}{15}$$

Dividing by 15 undoes the multiplication by 15.

$$a_{1}=\frac{15-5abz}{15}$$

Divide 15-5baz by 15.

$$a_{1}=-\frac{abz}{3}+1$$