Solve for x
x = \frac{18}{11} = 1\frac{7}{11} \approx 1.636363636
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15-x^{2}=100-\left(121-22x+x^{2}\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(11-x\right)^{2}.
15-x^{2}=100-121+22x-x^{2}
To find the opposite of 121-22x+x^{2}, find the opposite of each term.
15-x^{2}=-21+22x-x^{2}
Subtract 121 from 100 to get -21.
15-x^{2}-22x=-21-x^{2}
Subtract 22x from both sides.
15-x^{2}-22x+x^{2}=-21
Add x^{2} to both sides.
15-22x=-21
Combine -x^{2} and x^{2} to get 0.
-22x=-21-15
Subtract 15 from both sides.
-22x=-36
Subtract 15 from -21 to get -36.
x=\frac{-36}{-22}
Divide both sides by -22.
x=\frac{18}{11}
Reduce the fraction \frac{-36}{-22} to lowest terms by extracting and canceling out -2.
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