Solve 157/10-24/10+61/10

$$15 \frac { 7 } { 10 } - 2 \frac { 4 } { 10 } + 6 \frac { 1 } { 10 }$$

Evaluate

$$\frac{97}{5}=19.4$$

Solution Steps

Multiply 15 and 10 to get 150.

$$\frac{150+7}{10}-\frac{2\times 10+4}{10}+\frac{6\times 10+1}{10}$$

Add 150 and 7 to get 157.

$$\frac{157}{10}-\frac{2\times 10+4}{10}+\frac{6\times 10+1}{10}$$

Multiply 2 and 10 to get 20.

$$\frac{157}{10}-\frac{20+4}{10}+\frac{6\times 10+1}{10}$$

Add 20 and 4 to get 24.

$$\frac{157}{10}-\frac{24}{10}+\frac{6\times 10+1}{10}$$

Since \frac{157}{10} and \frac{24}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{157-24}{10}+\frac{6\times 10+1}{10}$$

Subtract 24 from 157 to get 133.

$$\frac{133}{10}+\frac{6\times 10+1}{10}$$

Multiply 6 and 10 to get 60.

$$\frac{133}{10}+\frac{60+1}{10}$$

Add 60 and 1 to get 61.

$$\frac{133}{10}+\frac{61}{10}$$

Since \frac{133}{10} and \frac{61}{10} have the same denominator, add them by adding their numerators.

$$\frac{133+61}{10}$$

Add 133 and 61 to get 194.

$$\frac{194}{10}$$

Reduce the fraction \frac{194}{10} to lowest terms by extracting and canceling out 2.

$$\frac{97}{5}$$

Factor

$$\frac{97}{5} = 19\frac{2}{5} = 19.4$$