Solve 153/4*2/3quad21/2

$$15 \frac { 3 } { 4 } \times \frac { 2 } { 3 } \quad \frac { 21 } { 2 }$$

Evaluate

$$\frac{441}{4}=110.25$$

Solution Steps

Multiply 15 and 4 to get 60.

$$\frac{60+3}{4}\times \frac{2}{3}\times \frac{21}{2}$$

Add 60 and 3 to get 63.

$$\frac{63}{4}\times \frac{2}{3}\times \frac{21}{2}$$

Multiply \frac{63}{4} times \frac{2}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{63\times 2}{4\times 3}\times \frac{21}{2}$$

Do the multiplications in the fraction \frac{63\times 2}{4\times 3}.

$$\frac{126}{12}\times \frac{21}{2}$$

Reduce the fraction \frac{126}{12} to lowest terms by extracting and canceling out 6.

$$\frac{21}{2}\times \frac{21}{2}$$

Multiply \frac{21}{2} times \frac{21}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{21\times 21}{2\times 2}$$

Do the multiplications in the fraction \frac{21\times 21}{2\times 2}.

$$\frac{441}{4}$$

Factor

$$\frac{3 ^ {2} \cdot 7 ^ {2}}{2 ^ {2}} = 110\frac{1}{4} = 110.25$$