Solve 1513/15+(-2134)+142/15+(-633/50)

$$15 \frac { 13 } { 15 } + ( - 2134 ) + 14 \frac { 2 } { 15 } + ( - 6 \frac { 33 } { 50 } )$$

Evaluate

$$-\frac{105533}{50}=-2110.66$$

Solution Steps

Multiply 15 and 15 to get 225.

$$\frac{225+13}{15}-2134+\frac{14\times 15+2}{15}-\frac{6\times 50+33}{50}$$

Add 225 and 13 to get 238.

$$\frac{238}{15}-2134+\frac{14\times 15+2}{15}-\frac{6\times 50+33}{50}$$

Convert 2134 to fraction \frac{32010}{15}.

$$\frac{238}{15}-\frac{32010}{15}+\frac{14\times 15+2}{15}-\frac{6\times 50+33}{50}$$

Since \frac{238}{15} and \frac{32010}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{238-32010}{15}+\frac{14\times 15+2}{15}-\frac{6\times 50+33}{50}$$

Subtract 32010 from 238 to get -31772.

$$-\frac{31772}{15}+\frac{14\times 15+2}{15}-\frac{6\times 50+33}{50}$$

Multiply 14 and 15 to get 210.

$$-\frac{31772}{15}+\frac{210+2}{15}-\frac{6\times 50+33}{50}$$

Add 210 and 2 to get 212.

$$-\frac{31772}{15}+\frac{212}{15}-\frac{6\times 50+33}{50}$$

Since -\frac{31772}{15} and \frac{212}{15} have the same denominator, add them by adding their numerators.

$$\frac{-31772+212}{15}-\frac{6\times 50+33}{50}$$

Add -31772 and 212 to get -31560.

$$\frac{-31560}{15}-\frac{6\times 50+33}{50}$$

Divide -31560 by 15 to get -2104.

$$-2104-\frac{6\times 50+33}{50}$$

Multiply 6 and 50 to get 300.

$$-2104-\frac{300+33}{50}$$

Add 300 and 33 to get 333.

$$-2104-\frac{333}{50}$$

Convert -2104 to fraction -\frac{105200}{50}.

$$-\frac{105200}{50}-\frac{333}{50}$$

Since -\frac{105200}{50} and \frac{333}{50} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-105200-333}{50}$$

Subtract 333 from -105200 to get -105533.

$$-\frac{105533}{50}$$

Factor

$$-\frac{105533}{50} = -2110\frac{33}{50} = -2110.66$$