Solve 15^{3}-2[2^4-2^2*(2^3-3)]+10^3

$$15 ^ { 3 } - 2 [ 2 ^ { 4 } - 2 ^ { 2 } \cdot ( 2 ^ { 3 } - 3 ) ] + 10 ^ { 3 }$$

Evaluate

$$4383$$

Solution Steps

Calculate 15 to the power of 3 and get 3375.

$$3375-2\left(2^{4}-2^{2}\left(2^{3}-3\right)\right)+10^{3}$$

Calculate 2 to the power of 4 and get 16.

$$3375-2\left(16-2^{2}\left(2^{3}-3\right)\right)+10^{3}$$

Calculate 2 to the power of 2 and get 4.

$$3375-2\left(16-4\left(2^{3}-3\right)\right)+10^{3}$$

Calculate 2 to the power of 3 and get 8.

$$3375-2\left(16-4\left(8-3\right)\right)+10^{3}$$

Subtract 3 from 8 to get 5.

$$3375-2\left(16-4\times 5\right)+10^{3}$$

Multiply 4 and 5 to get 20.

$$3375-2\left(16-20\right)+10^{3}$$

Subtract 20 from 16 to get -4.

$$3375-2\left(-4\right)+10^{3}$$

Multiply 2 and -4 to get -8.

$$3375-\left(-8\right)+10^{3}$$

The opposite of -8 is 8.

$$3375+8+10^{3}$$

Add 3375 and 8 to get 3383.

$$3383+10^{3}$$

Calculate 10 to the power of 3 and get 1000.

$$3383+1000$$

Add 3383 and 1000 to get 4383.

$$4383$$

Factor

$$3^{2}\times 487$$