Solve 15:(3-2+4)-(7-3+5*2)+7*(3-2*4)*(2*2-4)

$$15 : ( 3 - 2 + 4 ) - ( 7 - 3 + 5 \cdot 2 ) + 7 \cdot ( 3 - 2 \cdot 4 ) \cdot ( 2 \cdot 2 - 4 )$$

Evaluate

$$-11$$

Solution Steps

Subtract 2 from 3 to get 1.

$$\frac{15}{1+4}-\left(7-3+5\times 2\right)+7\left(3-2\times 4\right)\left(2\times 2-4\right)$$

Add 1 and 4 to get 5.

$$\frac{15}{5}-\left(7-3+5\times 2\right)+7\left(3-2\times 4\right)\left(2\times 2-4\right)$$

Divide 15 by 5 to get 3.

$$3-\left(7-3+5\times 2\right)+7\left(3-2\times 4\right)\left(2\times 2-4\right)$$

Subtract 3 from 7 to get 4.

$$3-\left(4+5\times 2\right)+7\left(3-2\times 4\right)\left(2\times 2-4\right)$$

Multiply 5 and 2 to get 10.

$$3-\left(4+10\right)+7\left(3-2\times 4\right)\left(2\times 2-4\right)$$

Add 4 and 10 to get 14.

$$3-14+7\left(3-2\times 4\right)\left(2\times 2-4\right)$$

Subtract 14 from 3 to get -11.

$$-11+7\left(3-2\times 4\right)\left(2\times 2-4\right)$$

Multiply 2 and 4 to get 8.

$$-11+7\left(3-8\right)\left(2\times 2-4\right)$$

Subtract 8 from 3 to get -5.

$$-11+7\left(-5\right)\left(2\times 2-4\right)$$

Multiply 7 and -5 to get -35.

$$-11-35\left(2\times 2-4\right)$$

Multiply 2 and 2 to get 4.

$$-11-35\left(4-4\right)$$

Subtract 4 from 4 to get 0.

$$-11-35\times 0$$

Multiply -35 and 0 to get 0.

$$-11+0$$

Add -11 and 0 to get -11.

$$-11$$

Factor

$$-11$$