Solve 152/5-63/5-63/4

$$15 \frac { 2 } { 5 } - 6 \frac { 3 } { 5 } - 6 \frac { 3 } { 4 }$$

Evaluate

$$\frac{41}{20}=2.05$$

Solution Steps

Multiply 15 and 5 to get 75.

$$\frac{75+2}{5}-\frac{6\times 5+3}{5}-\frac{6\times 4+3}{4}$$

Add 75 and 2 to get 77.

$$\frac{77}{5}-\frac{6\times 5+3}{5}-\frac{6\times 4+3}{4}$$

Multiply 6 and 5 to get 30.

$$\frac{77}{5}-\frac{30+3}{5}-\frac{6\times 4+3}{4}$$

Add 30 and 3 to get 33.

$$\frac{77}{5}-\frac{33}{5}-\frac{6\times 4+3}{4}$$

Since \frac{77}{5} and \frac{33}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{77-33}{5}-\frac{6\times 4+3}{4}$$

Subtract 33 from 77 to get 44.

$$\frac{44}{5}-\frac{6\times 4+3}{4}$$

Multiply 6 and 4 to get 24.

$$\frac{44}{5}-\frac{24+3}{4}$$

Add 24 and 3 to get 27.

$$\frac{44}{5}-\frac{27}{4}$$

Least common multiple of 5 and 4 is 20. Convert \frac{44}{5} and \frac{27}{4} to fractions with denominator 20.

$$\frac{176}{20}-\frac{135}{20}$$

Since \frac{176}{20} and \frac{135}{20} have the same denominator, subtract them by subtracting their numerators.

$$\frac{176-135}{20}$$

Subtract 135 from 176 to get 41.

$$\frac{41}{20}$$

Factor

$$\frac{41}{2 ^ {2} \cdot 5} = 2\frac{1}{20} = 2.05$$