Solve 144+left(44-xright)^2=x^2

$$144+ { \left(44-x \right) }^{ 2 } = { x }^{ 2 }$$

Solve for x

$$x = \frac{260}{11} = 23\frac{7}{11} \approx 23.636363636$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(44-x\right)^{2}.

$$144+1936-88x+x^{2}=x^{2}$$

Add 144 and 1936 to get 2080.

$$2080-88x+x^{2}=x^{2}$$

Subtract x^{2} from both sides.

$$2080-88x+x^{2}-x^{2}=0$$

Combine x^{2} and -x^{2} to get 0.

$$2080-88x=0$$

Subtract 2080 from both sides. Anything subtracted from zero gives its negation.

$$-88x=-2080$$

Divide both sides by -88.

$$x=\frac{-2080}{-88}$$

Reduce the fraction \frac{-2080}{-88} to lowest terms by extracting and canceling out -8.

$$x=\frac{260}{11}$$