Solve 1435div14

$$1435 \div 14$$

Evaluate

$$\frac{205}{2}=102.5$$

Steps For Long Division Method

Use the 1^{st} digit 1 from dividend 1435

$$\begin{array}{l}\phantom{14)}\phantom{1}\\14\overline{)1435}\\\end{array}$$

Since 1 is less than 14, use the next digit 4 from dividend 1435 and add 0 to the quotient

$$\begin{array}{l}\phantom{14)}0\phantom{2}\\14\overline{)1435}\\\end{array}$$

Use the 2^{nd} digit 4 from dividend 1435

$$\begin{array}{l}\phantom{14)}0\phantom{3}\\14\overline{)1435}\\\end{array}$$

Find closest multiple of 14 to 14. We see that 1 \times 14 = 14 is the nearest. Now subtract 14 from 14 to get reminder 0. Add 1 to quotient.

$$\begin{array}{l}\phantom{14)}01\phantom{4}\\14\overline{)1435}\\\phantom{14)}\underline{\phantom{}14\phantom{99}}\\\phantom{14)99}0\\\end{array}$$

Use the 3^{rd} digit 3 from dividend 1435

$$\begin{array}{l}\phantom{14)}01\phantom{5}\\14\overline{)1435}\\\phantom{14)}\underline{\phantom{}14\phantom{99}}\\\phantom{14)99}3\\\end{array}$$

Since 3 is less than 14, use the next digit 5 from dividend 1435 and add 0 to the quotient

$$\begin{array}{l}\phantom{14)}010\phantom{6}\\14\overline{)1435}\\\phantom{14)}\underline{\phantom{}14\phantom{99}}\\\phantom{14)99}3\\\end{array}$$

Use the 4^{th} digit 5 from dividend 1435

$$\begin{array}{l}\phantom{14)}010\phantom{7}\\14\overline{)1435}\\\phantom{14)}\underline{\phantom{}14\phantom{99}}\\\phantom{14)99}35\\\end{array}$$

Find closest multiple of 14 to 35. We see that 2 \times 14 = 28 is the nearest. Now subtract 28 from 35 to get reminder 7. Add 2 to quotient.

$$\begin{array}{l}\phantom{14)}0102\phantom{8}\\14\overline{)1435}\\\phantom{14)}\underline{\phantom{}14\phantom{99}}\\\phantom{14)99}35\\\phantom{14)}\underline{\phantom{99}28\phantom{}}\\\phantom{14)999}7\\\end{array}$$

Since 7 is less than 14, stop the division. The reminder is 7. The topmost line 0102 is the quotient. Remove all zeros at the start of the quotient to get the actual quotient 102.

$$\text{Quotient: }102 \text{Reminder: }7$$

Factor

$$\frac{5 \cdot 41}{2} = 102\frac{1}{2} = 102.5$$