Solve 143/4div(21/4+1/8)

$$143 / 4 \div ( 2 \frac { 1 } { 4 } + \frac { 1 } { 8 } )$$

Evaluate

$$\frac{286}{19}\approx 15.052631579$$

Solution Steps

Multiply 2 and 4 to get 8.

$$\frac{\frac{143}{4}}{\frac{8+1}{4}+\frac{1}{8}}$$

Add 8 and 1 to get 9.

$$\frac{\frac{143}{4}}{\frac{9}{4}+\frac{1}{8}}$$

Least common multiple of 4 and 8 is 8. Convert \frac{9}{4} and \frac{1}{8} to fractions with denominator 8.

$$\frac{\frac{143}{4}}{\frac{18}{8}+\frac{1}{8}}$$

Since \frac{18}{8} and \frac{1}{8} have the same denominator, add them by adding their numerators.

$$\frac{\frac{143}{4}}{\frac{18+1}{8}}$$

Add 18 and 1 to get 19.

$$\frac{\frac{143}{4}}{\frac{19}{8}}$$

Divide \frac{143}{4} by \frac{19}{8} by multiplying \frac{143}{4} by the reciprocal of \frac{19}{8}.

$$\frac{143}{4}\times \frac{8}{19}$$

Multiply \frac{143}{4} times \frac{8}{19} by multiplying numerator times numerator and denominator times denominator.

$$\frac{143\times 8}{4\times 19}$$

Do the multiplications in the fraction \frac{143\times 8}{4\times 19}.

$$\frac{1144}{76}$$

Reduce the fraction \frac{1144}{76} to lowest terms by extracting and canceling out 4.

$$\frac{286}{19}$$

Factor

$$\frac{2 \cdot 11 \cdot 13}{19} = 15\frac{1}{19} = 15.052631578947368$$