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14x+\frac{1}{5}-\frac{2}{3}=38x
Reduce the fraction \frac{8}{12} to lowest terms by extracting and canceling out 4.
14x+\frac{3}{15}-\frac{10}{15}=38x
Least common multiple of 5 and 3 is 15. Convert \frac{1}{5} and \frac{2}{3} to fractions with denominator 15.
14x+\frac{3-10}{15}=38x
Since \frac{3}{15} and \frac{10}{15} have the same denominator, subtract them by subtracting their numerators.
14x-\frac{7}{15}=38x
Subtract 10 from 3 to get -7.
14x-\frac{7}{15}-38x=0
Subtract 38x from both sides.
-24x-\frac{7}{15}=0
Combine 14x and -38x to get -24x.
-24x=\frac{7}{15}
Add \frac{7}{15} to both sides. Anything plus zero gives itself.
x=\frac{\frac{7}{15}}{-24}
Divide both sides by -24.
x=\frac{7}{15\left(-24\right)}
Express \frac{\frac{7}{15}}{-24} as a single fraction.
x=\frac{7}{-360}
Multiply 15 and -24 to get -360.
x=-\frac{7}{360}
Fraction \frac{7}{-360} can be rewritten as -\frac{7}{360} by extracting the negative sign.