Solve 14d+11-4d+2-6-2d

$$14 d + 11 - 4 d + 2 - 6 - 2 d$$

Evaluate

$$8d+7$$

Solution Steps

Combine 14d and -4d to get 10d.

$$10d+11+2-6-2d$$

Add 11 and 2 to get 13.

$$10d+13-6-2d$$

Subtract 6 from 13 to get 7.

$$10d+7-2d$$

Combine 10d and -2d to get 8d.

$$8d+7$$

Differentiate w.r.t. d

$$8$$

Steps Using Derivative Rule for Sum

Combine 14d and -4d to get 10d.

$$\frac{\mathrm{d}}{\mathrm{d}d}(10d+11+2-6-2d)$$

Add 11 and 2 to get 13.

$$\frac{\mathrm{d}}{\mathrm{d}d}(10d+13-6-2d)$$

Subtract 6 from 13 to get 7.

$$\frac{\mathrm{d}}{\mathrm{d}d}(10d+7-2d)$$

Combine 10d and -2d to get 8d.

$$\frac{\mathrm{d}}{\mathrm{d}d}(8d+7)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$8d^{1-1}$$

Subtract 1 from 1.

$$8d^{0}$$

For any term t except 0, t^{0}=1.

$$8\times 1$$

For any term t, t\times 1=t and 1t=t.

$$8$$