Solve 14b^2-71b^2=0

$$14 b ^ { 2 } - 71 b ^ { 2 } = 0$$

Solve for b

$$b=0$$

Steps by Finding Square Root

Combine 14b^{2} and -71b^{2} to get -57b^{2}.

$$-57b^{2}=0$$

Divide both sides by -57. Zero divided by any non-zero number gives zero.

$$b^{2}=0$$

Take the square root of both sides of the equation.

$$b=0 b=0$$

The equation is now solved. Solutions are the same.

$$b=0$$

Steps Using the Quadratic Formula

Combine 14b^{2} and -71b^{2} to get -57b^{2}.

$$-57b^{2}=0$$

Divide both sides by -57. Zero divided by any non-zero number gives zero.

$$b^{2}=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$b=\frac{0±\sqrt{0^{2}}}{2}$$

Take the square root of 0^{2}.

$$b=\frac{0±0}{2}$$

Divide 0 by 2.

$$b=0$$