Solve 14-3/2+19-12

$$14 - \frac { 3 } { 2 } + 19 - 12$$

Evaluate

$$\frac{39}{2}=19.5$$

Solution Steps

Convert 14 to fraction \frac{28}{2}.

$$\frac{28}{2}-\frac{3}{2}+19-12$$

Since \frac{28}{2} and \frac{3}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{28-3}{2}+19-12$$

Subtract 3 from 28 to get 25.

$$\frac{25}{2}+19-12$$

Convert 19 to fraction \frac{38}{2}.

$$\frac{25}{2}+\frac{38}{2}-12$$

Since \frac{25}{2} and \frac{38}{2} have the same denominator, add them by adding their numerators.

$$\frac{25+38}{2}-12$$

Add 25 and 38 to get 63.

$$\frac{63}{2}-12$$

Convert 12 to fraction \frac{24}{2}.

$$\frac{63}{2}-\frac{24}{2}$$

Since \frac{63}{2} and \frac{24}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{63-24}{2}$$

Subtract 24 from 63 to get 39.

$$\frac{39}{2}$$

Factor

$$\frac{3 \cdot 13}{2} = 19\frac{1}{2} = 19.5$$