Solve 14^{2}*3^{2}+5^{0}-3*16*3^{2}-2^{5}-8^{0}-(3^{4}-4^{3})]1-[(4+3^2)^2:13+(5^4:5^2)*2]

$$14 ^ { 2 } \times 3 ^ { 2 } + 5 ^ { 0 } - 3 \times 16 \times 3 ^ { 2 } - 2 ^ { 5 } - 8 ^ { 0 } - ( 3 ^ { 4 } - 4 ^ { 3 } ) ] 1 - [ ( 4 + 3 ^ { 2 } ) ^ { 2 } : 13 + ( 5 ^ { 4 } : 5 ^ { 2 } ) \times 2 ]$$

Evaluate

$$1283$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$14^{2}\times 3^{2}+5^{0}-3^{3}\times 16-2^{5}-8^{0}-\left(3^{4}-4^{3}\right)$$

Calculate 14 to the power of 2 and get 196.

$$196\times 3^{2}+5^{0}-3^{3}\times 16-2^{5}-8^{0}-\left(3^{4}-4^{3}\right)$$

Calculate 3 to the power of 2 and get 9.

$$196\times 9+5^{0}-3^{3}\times 16-2^{5}-8^{0}-\left(3^{4}-4^{3}\right)$$

Multiply 196 and 9 to get 1764.

$$1764+5^{0}-3^{3}\times 16-2^{5}-8^{0}-\left(3^{4}-4^{3}\right)$$

Calculate 5 to the power of 0 and get 1.

$$1764+1-3^{3}\times 16-2^{5}-8^{0}-\left(3^{4}-4^{3}\right)$$

Add 1764 and 1 to get 1765.

$$1765-3^{3}\times 16-2^{5}-8^{0}-\left(3^{4}-4^{3}\right)$$

Calculate 3 to the power of 3 and get 27.

$$1765-27\times 16-2^{5}-8^{0}-\left(3^{4}-4^{3}\right)$$

Multiply 27 and 16 to get 432.

$$1765-432-2^{5}-8^{0}-\left(3^{4}-4^{3}\right)$$

Subtract 432 from 1765 to get 1333.

$$1333-2^{5}-8^{0}-\left(3^{4}-4^{3}\right)$$

Calculate 2 to the power of 5 and get 32.

$$1333-32-8^{0}-\left(3^{4}-4^{3}\right)$$

Subtract 32 from 1333 to get 1301.

$$1301-8^{0}-\left(3^{4}-4^{3}\right)$$

Calculate 8 to the power of 0 and get 1.

$$1301-1-\left(3^{4}-4^{3}\right)$$

Subtract 1 from 1301 to get 1300.

$$1300-\left(3^{4}-4^{3}\right)$$

Calculate 3 to the power of 4 and get 81.

$$1300-\left(81-4^{3}\right)$$

Calculate 4 to the power of 3 and get 64.

$$1300-\left(81-64\right)$$

Subtract 64 from 81 to get 17.

$$1300-17$$

Subtract 17 from 1300 to get 1283.

$$1283$$

Factor

$$1283$$