Solve 14+10ygeq3(y+14)

$$14 + 10 y \geq 3 ( y + 14 )$$

Solve for y

$$y\geq 4$$

Solution Steps

Use the distributive property to multiply 3 by y+14.

$$14+10y\geq 3y+42$$

Subtract 3y from both sides.

$$14+10y-3y\geq 42$$

Combine 10y and -3y to get 7y.

$$14+7y\geq 42$$

Subtract 14 from both sides.

$$7y\geq 42-14$$

Subtract 14 from 42 to get 28.

$$7y\geq 28$$

Divide both sides by 7. Since 7 is positive, the inequality direction remains the same.

$$y\geq \frac{28}{7}$$

Divide 28 by 7 to get 4.

$$y\geq 4$$