Solve 1300div102

$$1300 \div 102$$

Evaluate

$$\frac{650}{51}\approx 12.745098039$$

Steps For Long Division Method

Use the 1^{st} digit 1 from dividend 1300

$$\begin{array}{l}\phantom{102)}\phantom{1}\\102\overline{)1300}\\\end{array}$$

Since 1 is less than 102, use the next digit 3 from dividend 1300 and add 0 to the quotient

$$\begin{array}{l}\phantom{102)}0\phantom{2}\\102\overline{)1300}\\\end{array}$$

Use the 2^{nd} digit 3 from dividend 1300

$$\begin{array}{l}\phantom{102)}0\phantom{3}\\102\overline{)1300}\\\end{array}$$

Since 13 is less than 102, use the next digit 0 from dividend 1300 and add 0 to the quotient

$$\begin{array}{l}\phantom{102)}00\phantom{4}\\102\overline{)1300}\\\end{array}$$

Use the 3^{rd} digit 0 from dividend 1300

$$\begin{array}{l}\phantom{102)}00\phantom{5}\\102\overline{)1300}\\\end{array}$$

Find closest multiple of 102 to 130. We see that 1 \times 102 = 102 is the nearest. Now subtract 102 from 130 to get reminder 28. Add 1 to quotient.

$$\begin{array}{l}\phantom{102)}001\phantom{6}\\102\overline{)1300}\\\phantom{102)}\underline{\phantom{}102\phantom{9}}\\\phantom{102)9}28\\\end{array}$$

Use the 4^{th} digit 0 from dividend 1300

$$\begin{array}{l}\phantom{102)}001\phantom{7}\\102\overline{)1300}\\\phantom{102)}\underline{\phantom{}102\phantom{9}}\\\phantom{102)9}280\\\end{array}$$

Find closest multiple of 102 to 280. We see that 2 \times 102 = 204 is the nearest. Now subtract 204 from 280 to get reminder 76. Add 2 to quotient.

$$\begin{array}{l}\phantom{102)}0012\phantom{8}\\102\overline{)1300}\\\phantom{102)}\underline{\phantom{}102\phantom{9}}\\\phantom{102)9}280\\\phantom{102)}\underline{\phantom{9}204\phantom{}}\\\phantom{102)99}76\\\end{array}$$

Since 76 is less than 102, stop the division. The reminder is 76. The topmost line 0012 is the quotient. Remove all zeros at the start of the quotient to get the actual quotient 12.

$$\text{Quotient: }12 \text{Reminder: }76$$

Factor

$$\frac{2 \cdot 5 ^ {2} \cdot 13}{3 \cdot 17} = 12\frac{38}{51} = 12.745098039215685$$