Solve 130(50y+40x+xy-3400)=0

$$130(50y+40x+xy-3400)=0$$

Solve for x

$$x=-\frac{50\left(y-68\right)}{y+40}$$

$$y\neq -40$$

Steps for Solving Linear Equation

Divide both sides by 130. Zero divided by any non-zero number gives zero.

$$50y+40x+xy-3400=0$$

Subtract 50y from both sides. Anything subtracted from zero gives its negation.

$$40x+xy-3400=-50y$$

Add 3400 to both sides.

$$40x+xy=-50y+3400$$

Combine all terms containing x.

$$\left(40+y\right)x=-50y+3400$$

The equation is in standard form.

$$\left(y+40\right)x=3400-50y$$

Divide both sides by 40+y.

$$\frac{\left(y+40\right)x}{y+40}=\frac{3400-50y}{y+40}$$

Dividing by 40+y undoes the multiplication by 40+y.

$$x=\frac{3400-50y}{y+40}$$

Divide -50y+3400 by 40+y.

$$x=\frac{50\left(68-y\right)}{y+40}$$

Solve for y

$$y=-\frac{40\left(x-85\right)}{x+50}$$

$$x\neq -50$$

Steps for Solving Linear Equation

Divide both sides by 130. Zero divided by any non-zero number gives zero.

$$50y+40x+xy-3400=0$$

Subtract 40x from both sides. Anything subtracted from zero gives its negation.

$$50y+xy-3400=-40x$$

Add 3400 to both sides.

$$50y+xy=-40x+3400$$

Combine all terms containing y.

$$\left(50+x\right)y=-40x+3400$$

The equation is in standard form.

$$\left(x+50\right)y=3400-40x$$

Divide both sides by 50+x.

$$\frac{\left(x+50\right)y}{x+50}=\frac{3400-40x}{x+50}$$

Dividing by 50+x undoes the multiplication by 50+x.

$$y=\frac{3400-40x}{x+50}$$

Divide -40x+3400 by 50+x.

$$y=\frac{40\left(85-x\right)}{x+50}$$