Solve for x
x=2y+3
Solve for y
y=\frac{x-3}{2}
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13x-39=26y
Add 26y to both sides. Anything plus zero gives itself.
13x=26y+39
Add 39 to both sides.
\frac{13x}{13}=\frac{26y+39}{13}
Divide both sides by 13.
x=\frac{26y+39}{13}
Dividing by 13 undoes the multiplication by 13.
x=2y+3
Divide 26y+39 by 13.
-26y-39=-13x
Subtract 13x from both sides. Anything subtracted from zero gives its negation.
-26y=-13x+39
Add 39 to both sides.
-26y=39-13x
The equation is in standard form.
\frac{-26y}{-26}=\frac{39-13x}{-26}
Divide both sides by -26.
y=\frac{39-13x}{-26}
Dividing by -26 undoes the multiplication by -26.
y=\frac{x-3}{2}
Divide -13x+39 by -26.
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