Solve 13-(1/2-3)+1/4]*(-5)

$$13 - ( \frac { 1 } { 2 } - 3 ) + \frac { 1 } { 4 } ] \cdot ( - 5 )$$

Evaluate

$$\frac{63}{4}=15.75$$

Solution Steps

Convert 3 to fraction \frac{6}{2}.

$$13-\left(\frac{1}{2}-\frac{6}{2}\right)+\frac{1}{4}$$

Since \frac{1}{2} and \frac{6}{2} have the same denominator, subtract them by subtracting their numerators.

$$13-\frac{1-6}{2}+\frac{1}{4}$$

Subtract 6 from 1 to get -5.

$$13-\left(-\frac{5}{2}\right)+\frac{1}{4}$$

The opposite of -\frac{5}{2} is \frac{5}{2}.

$$13+\frac{5}{2}+\frac{1}{4}$$

Convert 13 to fraction \frac{26}{2}.

$$\frac{26}{2}+\frac{5}{2}+\frac{1}{4}$$

Since \frac{26}{2} and \frac{5}{2} have the same denominator, add them by adding their numerators.

$$\frac{26+5}{2}+\frac{1}{4}$$

Add 26 and 5 to get 31.

$$\frac{31}{2}+\frac{1}{4}$$

Least common multiple of 2 and 4 is 4. Convert \frac{31}{2} and \frac{1}{4} to fractions with denominator 4.

$$\frac{62}{4}+\frac{1}{4}$$

Since \frac{62}{4} and \frac{1}{4} have the same denominator, add them by adding their numerators.

$$\frac{62+1}{4}$$

Add 62 and 1 to get 63.

$$\frac{63}{4}$$

Factor

$$\frac{3 ^ {2} \cdot 7}{2 ^ {2}} = 15\frac{3}{4} = 15.75$$