Solve 135/8div(-229/40)

$$13 \frac{ 5 }{ 8 } \div (-2 \frac{ 29 }{ 40 } )$$

Evaluate

$$-5$$

Solution Steps

Multiply 13 and 8 to get 104.

$$\frac{\frac{104+5}{8}}{-\frac{2\times 40+29}{40}}$$

Add 104 and 5 to get 109.

$$\frac{\frac{109}{8}}{-\frac{2\times 40+29}{40}}$$

Multiply 2 and 40 to get 80.

$$\frac{\frac{109}{8}}{-\frac{80+29}{40}}$$

Add 80 and 29 to get 109.

$$\frac{\frac{109}{8}}{-\frac{109}{40}}$$

Divide \frac{109}{8} by -\frac{109}{40} by multiplying \frac{109}{8} by the reciprocal of -\frac{109}{40}.

$$\frac{109}{8}\left(-\frac{40}{109}\right)$$

Multiply \frac{109}{8} times -\frac{40}{109} by multiplying numerator times numerator and denominator times denominator.

$$\frac{109\left(-40\right)}{8\times 109}$$

Cancel out 109 in both numerator and denominator.

$$\frac{-40}{8}$$

Divide -40 by 8 to get -5.

$$-5$$

Factor

$$-5$$