Solve 135/6-(-3/4)+5/6--7/12

$$13 \frac{ 5 }{ 6 } -(- \frac{ 3 }{ 4 } )+ \frac{ 5 }{ 6 } -- \frac{ 7 }{ 12 }$$

Evaluate

$$16$$

Solution Steps

Multiply 13 and 6 to get 78.

$$\frac{78+5}{6}-\left(-\frac{3}{4}\right)+\frac{5}{6}-\left(-\frac{7}{12}\right)$$

Add 78 and 5 to get 83.

$$\frac{83}{6}-\left(-\frac{3}{4}\right)+\frac{5}{6}-\left(-\frac{7}{12}\right)$$

The opposite of -\frac{3}{4} is \frac{3}{4}.

$$\frac{83}{6}+\frac{3}{4}+\frac{5}{6}-\left(-\frac{7}{12}\right)$$

Least common multiple of 6 and 4 is 12. Convert \frac{83}{6} and \frac{3}{4} to fractions with denominator 12.

$$\frac{166}{12}+\frac{9}{12}+\frac{5}{6}-\left(-\frac{7}{12}\right)$$

Since \frac{166}{12} and \frac{9}{12} have the same denominator, add them by adding their numerators.

$$\frac{166+9}{12}+\frac{5}{6}-\left(-\frac{7}{12}\right)$$

Add 166 and 9 to get 175.

$$\frac{175}{12}+\frac{5}{6}-\left(-\frac{7}{12}\right)$$

Least common multiple of 12 and 6 is 12. Convert \frac{175}{12} and \frac{5}{6} to fractions with denominator 12.

$$\frac{175}{12}+\frac{10}{12}-\left(-\frac{7}{12}\right)$$

Since \frac{175}{12} and \frac{10}{12} have the same denominator, add them by adding their numerators.

$$\frac{175+10}{12}-\left(-\frac{7}{12}\right)$$

Add 175 and 10 to get 185.

$$\frac{185}{12}-\left(-\frac{7}{12}\right)$$

The opposite of -\frac{7}{12} is \frac{7}{12}.

$$\frac{185}{12}+\frac{7}{12}$$

Since \frac{185}{12} and \frac{7}{12} have the same denominator, add them by adding their numerators.

$$\frac{185+7}{12}$$

Add 185 and 7 to get 192.

$$\frac{192}{12}$$

Divide 192 by 12 to get 16.

$$16$$

Factor

$$2^{4}$$