Solve 133/5:6/5+3/6=(3/3divfrac{2}{6})

$$13 \frac { 3 } { 5 } : \frac { 6 } { 5 } + \frac { 3 } { 6 } = ( \frac { 3 } { 3 } \div \frac { 2 } { 6 } )$$

Verify

Solution Steps

Divide 3 by 3 to get 1.

$$\frac{\frac{13\times 5+3}{5}}{\frac{6}{5}}+\frac{3}{6}=\frac{1}{\frac{2}{6}}$$

Divide \frac{13\times 5+3}{5} by \frac{6}{5} by multiplying \frac{13\times 5+3}{5} by the reciprocal of \frac{6}{5}.

$$\frac{\left(13\times 5+3\right)\times 5}{5\times 6}+\frac{3}{6}=\frac{1}{\frac{2}{6}}$$

Cancel out 5 in both numerator and denominator.

$$\frac{3+5\times 13}{6}+\frac{3}{6}=\frac{1}{\frac{2}{6}}$$

Multiply 5 and 13 to get 65.

$$\frac{3+65}{6}+\frac{3}{6}=\frac{1}{\frac{2}{6}}$$

Add 3 and 65 to get 68.

$$\frac{68}{6}+\frac{3}{6}=\frac{1}{\frac{2}{6}}$$

Since \frac{68}{6} and \frac{3}{6} have the same denominator, add them by adding their numerators.

$$\frac{68+3}{6}=\frac{1}{\frac{2}{6}}$$

Add 68 and 3 to get 71.

$$\frac{71}{6}=\frac{1}{\frac{2}{6}}$$

Divide 1 by \frac{2}{6} by multiplying 1 by the reciprocal of \frac{2}{6}.

$$\frac{71}{6}=\frac{6}{2}$$

Divide 6 by 2 to get 3.

$$\frac{71}{6}=3$$

Convert 3 to fraction \frac{18}{6}.

$$\frac{71}{6}=\frac{18}{6}$$

Compare \frac{71}{6} and \frac{18}{6}.

$$\text{false}$$