Solve 131/4=(4*13)+1/4=47/41

$$13 \frac { 1 } { 4 } = \frac { ( 4 \times 13 ) + 1 } { 4 } = \frac { 47 } { 41 }$$

Verify

Solution Steps

Multiply 13 and 4 to get 52.

$$\frac{52+1}{4}=\frac{4\times 13+1}{4}\text{ and }\frac{4\times 13+1}{4}=\frac{47}{41}$$

Add 52 and 1 to get 53.

$$\frac{53}{4}=\frac{4\times 13+1}{4}\text{ and }\frac{4\times 13+1}{4}=\frac{47}{41}$$

Multiply 4 and 13 to get 52.

$$\frac{53}{4}=\frac{52+1}{4}\text{ and }\frac{4\times 13+1}{4}=\frac{47}{41}$$

Add 52 and 1 to get 53.

$$\frac{53}{4}=\frac{53}{4}\text{ and }\frac{4\times 13+1}{4}=\frac{47}{41}$$

Compare \frac{53}{4} and \frac{53}{4}.

$$\text{true}\text{ and }\frac{4\times 13+1}{4}=\frac{47}{41}$$

Multiply 4 and 13 to get 52.

$$\text{true}\text{ and }\frac{52+1}{4}=\frac{47}{41}$$

Add 52 and 1 to get 53.

$$\text{true}\text{ and }\frac{53}{4}=\frac{47}{41}$$

Least common multiple of 4 and 41 is 164. Convert \frac{53}{4} and \frac{47}{41} to fractions with denominator 164.

$$\text{true}\text{ and }\frac{2173}{164}=\frac{188}{164}$$

Compare \frac{2173}{164} and \frac{188}{164}.

$$\text{true}\text{ and }\text{false}$$

The conjunction of \text{true} and \text{false} is \text{false}.

$$\text{false}$$