Solve 13^2+19^2+2x-13*19=24^2

$$13 ^ { 2 } + 19 ^ { 2 } + 2 x - 13 \cdot 19 = 24 ^ { 2 }$$

Solve for x

$$x = \frac{293}{2} = 146\frac{1}{2} = 146.5$$

Steps for Solving Linear Equation

Calculate 13 to the power of 2 and get 169.

$$169+19^{2}+2x-13\times 19=24^{2}$$

Calculate 19 to the power of 2 and get 361.

$$169+361+2x-13\times 19=24^{2}$$

Add 169 and 361 to get 530.

$$530+2x-13\times 19=24^{2}$$

Multiply 13 and 19 to get 247.

$$530+2x-247=24^{2}$$

Subtract 247 from 530 to get 283.

$$283+2x=24^{2}$$

Calculate 24 to the power of 2 and get 576.

$$283+2x=576$$

Subtract 283 from both sides.

$$2x=576-283$$

Subtract 283 from 576 to get 293.

$$2x=293$$

Divide both sides by 2.

$$x=\frac{293}{2}$$