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Differentiate w.r.t. x_500
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\begin{array}{c}\phantom{\times99}12\\\underline{\times\phantom{9}500}\\\end{array}
First line up the numbers vertically and match the places from the right like this.
\begin{array}{c}\phantom{\times99}12\\\underline{\times\phantom{9}500}\\\phantom{\times9999}0\\\end{array}
Now multiply the first number with the 1^{st} digit in 2^{nd} number to get intermediate results. That is Multiply 12 with 0. Write the result 0 at the end leaving 0 spaces to the right like this.
\begin{array}{c}\phantom{\times99}12\\\underline{\times\phantom{9}500}\\\phantom{\times9999}0\\\phantom{\times999}0\phantom{9}\\\end{array}
Now multiply the first number with the 2^{nd} digit in 2^{nd} number to get intermediate results. That is Multiply 12 with 0. Write the result 0 at the end leaving 1 spaces to the right like this.
\begin{array}{c}\phantom{\times99}12\\\underline{\times\phantom{9}500}\\\phantom{\times9999}0\\\phantom{\times999}0\phantom{9}\\\underline{\phantom{\times}60\phantom{99}}\\\end{array}
Now multiply the first number with the 3^{rd} digit in 2^{nd} number to get intermediate results. That is Multiply 12 with 5. Write the result 60 at the end leaving 2 spaces to the right like this.
\begin{array}{c}\phantom{\times99}12\\\underline{\times\phantom{9}500}\\\phantom{\times9999}0\\\phantom{\times999}0\phantom{9}\\\underline{\phantom{\times}60\phantom{99}}\\\phantom{\times}6000\end{array}
Now add the intermediate results to get final answer.
12x_{500}^{1-1}
The derivative of ax^{n} is nax^{n-1}.
12x_{500}^{0}
Subtract 1 from 1.
12\times 1
For any term t except 0, t^{0}=1.
12
For any term t, t\times 1=t and 1t=t.