Solve for x
x=\frac{y-36}{12}
Solve for y
y=12\left(x+3\right)
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12x=-36+y
Add y to both sides.
12x=y-36
The equation is in standard form.
\frac{12x}{12}=\frac{y-36}{12}
Divide both sides by 12.
x=\frac{y-36}{12}
Dividing by 12 undoes the multiplication by 12.
x=\frac{y}{12}-3
Divide -36+y by 12.
-y=-36-12x
Subtract 12x from both sides.
-y=-12x-36
The equation is in standard form.
\frac{-y}{-1}=\frac{-12x-36}{-1}
Divide both sides by -1.
y=\frac{-12x-36}{-1}
Dividing by -1 undoes the multiplication by -1.
y=12x+36
Divide -36-12x by -1.
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