Solve for x
x=\frac{3y}{4}+\frac{1}{2}
Solve for y
y=\frac{4x-2}{3}
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12x=9y+12-6
Subtract 6 from both sides.
12x=9y+6
Subtract 6 from 12 to get 6.
\frac{12x}{12}=\frac{9y+6}{12}
Divide both sides by 12.
x=\frac{9y+6}{12}
Dividing by 12 undoes the multiplication by 12.
x=\frac{3y}{4}+\frac{1}{2}
Divide 9y+6 by 12.
9y+12=12x+6
Swap sides so that all variable terms are on the left hand side.
9y=12x+6-12
Subtract 12 from both sides.
9y=12x-6
Subtract 12 from 6 to get -6.
\frac{9y}{9}=\frac{12x-6}{9}
Divide both sides by 9.
y=\frac{12x-6}{9}
Dividing by 9 undoes the multiplication by 9.
y=\frac{4x-2}{3}
Divide 12x-6 by 9.
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